Modbus协议CRC的两种Delphi算法源码举例。在工控开发时经常用到.
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unit Unit1; interface uses Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms, Dialogs, StdCtrls; type TDataByte = array of byte; TForm1 = class(TForm) Button1: TButton; Edit1: TEdit; Label1: TLabel; Edit2: TEdit; procedure Button1Click(Sender: TObject); private { Private declarations } public { Public declarations } end; const CRCHi: array [0..255] of byte = ( $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40, $00, $C1, $81, $40, $01, $C0, $80, $41, $00, $C1, $81, $40, $01, $C0, $80, $41, $01, $C0, $80, $41, $00, $C1, $81, $40 ) ; CRCLo: array [0..255] of byte = ( $00, $C0, $C1, $01, $C3, $03, $02, $C2, $C6, $06, $07, $C7, $05, $C5, $C4, $04, $CC, $0C, $0D, $CD, $0F, $CF, $CE, $0E, $0A, $CA, $CB, $0B, $C9, $09, $08, $C8, $D8, $18, $19, $D9, $1B, $DB, $DA, $1A, $1E, $DE, $DF, $1F, $DD, $1D, $1C, $DC, $14, $D4, $D5, $15, $D7, $17, $16, $D6, $D2, $12, $13, $D3, $11, $D1, $D0, $10, $F0, $30, $31, $F1, $33, $F3, $F2, $32, $36, $F6, $F7, $37, $F5, $35, $34, $F4, $3C, $FC, $FD, $3D, $FF, $3F, $3E, $FE, $FA, $3A, $3B, $FB, $39, $F9, $F8, $38, $28, $E8, $E9, $29, $EB, $2B, $2A, $EA, $EE, $2E, $2F, $EF, $2D, $ED, $EC, $2C, $E4, $24, $25, $E5, $27, $E7, $E6, $26, $22, $E2, $E3, $23, $E1, $21, $20, $E0, $A0, $60, $61, $A1, $63, $A3, $A2, $62, $66, $A6, $A7, $67, $A5, $65, $64, $A4, $6C, $AC, $AD, $6D, $AF, $6F, $6E, $AE, $AA, $6A, $6B, $AB, $69, $A9, $A8, $68, $78, $B8, $B9, $79, $BB, $7B, $7A, $BA, $BE, $7E, $7F, $BF, $7D, $BD, $BC, $7C, $B4, $74, $75, $B5, $77, $B7, $B6, $76, $72, $B2, $B3, $73, $B1, $71, $70, $B0, $50, $90, $91, $51, $93, $53, $52, $92, $96, $56, $57, $97, $55, $95, $94, $54, $9C, $5C, $5D, $9D, $5F, $9F, $9E, $5E, $5A, $9A, $9B, $5B, $99, $59, $58, $98, $88, $48, $49, $89, $4B, $8B, $8A, $4A, $4E, $8E, $8F, $4F, $8D, $4D, $4C, $8C, $44, $84, $85, $45, $87, $47, $46, $86, $82, $42, $43, $83, $41, $81, $80, $40 ); var Form1: TForm1; implementation {$R *.dfm} function crc16(var dataaddress :byte; datalength: byte): word; var hi: byte; lo: byte; i: byte; index: byte; datadd: pbytearray; begin hi := $FF; lo := $FF; datadd := @dataaddress; i := 0; while (datalength > 0) do begin index := hi xor datadd^[i]; i := i + 1; hi := lo xor crchi[index]; lo := crclo[index]; datalength := datalength - 1; end; crc16 := hi shl 8 or lo; end; function ModBusCRC(Data: string): string; //生成modbus CRC数据 var CRC16Lo, CRC16Hi, CL, CH, UseHi, UseLo: Dword; i, index: integer; begin CRC16Lo := $FF; //CRC16Lo为CRC寄存器低8位 CRC16Hi := $FF; //CRC16Hi为CRC寄存器高8位 CL := $01; CH := $A0; // A001 H 是CRC－16多项式代码 for i := 1 to Length(Data) do begin CRC16Lo := CRC16Lo xor ord(Data[i]); //每一个数据与CRC寄存器异或 for index := 0 to 7 do begin UseHi := CRC16Hi; UseLo := CRC16Lo; CRC16Hi := CRC16Hi shr 1; CRC16Lo := CRC16Lo shr 1; //右移一位 if ((UseHi and $1) = $1) then //如果高位字节最后一位是1的话 CRC16Lo := CRC16Lo or $80; //低位字节右移后前面补1 if ((UseLo and $1) = $1) then //如果LSB 为1，则与多项式进行异或 begin CRC16Hi := CRC16Hi xor CH; CRC16Lo := CRC16Lo xor CL; end; end; end; Result := IntToHex(CRC16Lo, 2) + IntToHex(CRC16Hi, 2); end; procedure TForm1.Button1Click(Sender: TObject); var Data1 : TDataByte; c:word; i,l:integer; begin l := Length(Edit1.Text); Setlength(Data1,l); for i:=0 to l-1 do Data1[i]:= ord(Edit1.Text[i+1]); c:=CRC16(Data1[0],l); Edit2.Text:=('ModBusCRC='+ModBusCRC(Edit1.Text)+' CRC16='+ inttohex(c,4)); end; |
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